What are the values of the domain of the defined function of Reais in Reais by the function s of t equal to the square minus 5 times t plus 9, which define the image equal to 3? In a physical view imagine a car that travels through the function shown, and find out at which, or what moments it is in the position 3 units away.
a. 1 and 3.
b. 2 and 3.
c. 5.
d. 3 and 5.
e. 2 and 5.
To answer this question we have to know that the function is from reais to reais, and that the function is a second degree equation. We have that the image is equal to three, that is, the position that the car has to go is in the position of three units of distance. So we can put the three in the function and by solving the second degree equation we determine the time the car spends in position.
We can use the base formula. So we must replace the function values in the formula. And this gives us two values, 1 and 3. So the car passes in position 3 in two periods of time, in time 2 and then in time 3. This means that the car passed in 3 then returned and passed in 3 again. We can see this in the curve that shows the time when the car arrives at position 3 twice.
So alternative b is the correct one.