Let the path of a car be a function of Reais in Reais, defined by a function s of t, which is equal to twice the time t minus 3 all divided by 5. We call part t of the domain function , and we call the other part Image. If the image is minus three divided by four, what would be the value of the domain.
Transforming mathematically into a more physical mode, we have that the car reached the street position that has the value by the formula twice the time t minus 3 all divided by 5, this is called an image, the time it took to travel would be the domain .
So how long did it take to travel the distance we call an image?
a. -3/8.
B. 8/3.
c. 3/8.
d. 1.
e. 3.
We know how much the path was, which is -3 divided by 4, we have to mathematically value this is the image, and the image is also the function, so evenly we can solve the equation, until we find the time, which mathematically speaking is the domain . Solving the equation we find that time is -3 divided by 8 units of time. Which represents alternative A.
Transforming mathematically into a more physical mode, we have that the car reached the street position that has the value by the formula twice the time t minus 3 all divided by 5, this is called an image, the time it took to travel would be the domain .
So how long did it take to travel the distance we call an image?
a. -3/8.
B. 8/3.
c. 3/8.
d. 1.
e. 3.
We know how much the path was, which is -3 divided by 4, we have to mathematically value this is the image, and the image is also the function, so evenly we can solve the equation, until we find the time, which mathematically speaking is the domain . Solving the equation we find that time is -3 divided by 8 units of time. Which represents alternative A.