Three equilateral triangles and two squares form a flat figure as illustrated. Their centers are the vertices of an irregular pentagon, which is highlighted in the figure. If T is the area of each of the triangles and Q is the area of each of the squares, the area of this pentagon is:
When we look at the square we can see that the inner square is a quarter of the square. If we draw a straight line on the equilateral triangle, we can see that there are 3 equal triangles, and their internal angles are also equal, which makes the internal triangle one third of the triangle. So we have 2 squares, and 3 triangles, adding up these areas, we have the area of a triangle and half of a square. Which is seen in alternative C.
